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xnyan | 4 days ago
A modest bus holds 40-50 people. Most commuter traffic is single driver, single vehicle. I don't know to which power the difference in axle weight would have to be to surpass the efficiency gains of replacing 40 to 50 American sized SUVs with a city bus, but I suspect it's more than four.
XCabbage|3 days ago
(I don't really understand how the fourth power of axel weight thing can possibly be true, though. Why would joining two vehicles together into a mega vehicle with double the weight and double the wheel count suddenly cause the combined vehicle to inflict 16x more wear than before you joined the two together? It makes no sense.)
philwelch|3 days ago
A Ford F-150 weighs about 2 tons and has two axles, for an axle weight of 1 ton. 1^4=1.
A garbage truck weighs maybe 30 tons and has three axles, for an axle weight of 10 tons. 10^4=10,000.
So if you drive an F-150, you’re doing as much road damage driving down the street 10,000 times as the garbage truck does once. Rural areas that don’t have garbage trucks and just expect everyone to haul their garbage to the dump in the back of their pickups are onto something.
rkangel|3 days ago
So, scenario A:
Scenario B:adwf|3 days ago
In Europe, the numbers differ even more. Lighter weight cars typically 1.5-2 tons, a new London bus can be upto 18 tons when loaded - that's ~5-16 units of wear for the car to 104,976 units for the bus...
But this is all supposing we're optimising for road wear, which isn't really the point of a bus system.
ninalanyon|2 days ago
Doubling the weight and doubling the wheel count leaves the axle weight unchanged.