I love mathematicians. They give a complicated function, explaining how they derived each term, and then consider the problem solved, without bothering to give a number.
It's correct, of course, as the problem is solved, but most people would attempt a ballpark approximation in the end!
From Davis and Hersh's excellent book "The Mathematical Experience":
Professor John Wermer tells the story of how, when he was an undergraduate, he took a course in projective geometry from Oscar Zariski, one of the foremost figures in the field of algebraic geometry. Zariski's course was exceedingly general and Wermer, as a young student, was occasionally in need of clarification. "What would you get," he asked his teacher, "if you specialized the field F to the complex numbers?" Zariski answered, "Yes, just take F as the complex numbers."
It seems to me that we can get a pretty decent approximation as follows:
1. At any given time, Pr(oldest person <= age x) = Pr(one person <= age x)^N. So (over time) the median oldest-person age is the (1-2^-1/N) quantile of the age distribution. (For large N, this is roughly 1-log(2)/N.) (You can get that from actuarial tables, or use the Gompertz-Makeham approximation.)
2. So, crudely, the time between oldest-person deaths is comparable to either the expected lifetime of a person of the age found in step 1, or 1/Pr(someone of that age dies in a given year). (Both are approximations. The former will give shorter inter-death times.)
3. According to Wikipedia (which is always right, except when it's wrong), once you get old enough it's a decent approximation to say that that a Very Old Person has about a 50% chance of making it through any given year, and that figure doesn't depend very much on exactly how old they are.
Which would suggest that we should get a new oldest person about once every two years, and that for decent-sized populations (say, 1000 or more) the figure should depend only very weakly on population size.
If #3 is correct and at very advanced ages the mortality rate is roughly independent of age, it seems like this result shouldn't actually depend much on the details of the probability distributions. (The oldest person alive will almost always be very old.)
(You'd get quite different results if, e.g., there were a hard divinely-appointed cutoff at some particular age.)
As pointed out in 3.) the mortality hazard h(x) does not increase exponentially at very high ages as it does for ages 30 up to let's 80 or 90. Until then the Gompertz-Makeham hazard h(x)= alpha * exp(betax) + gamma approximates adult mortality very well. At higher ages mortality begins to decelerate and, most likely, reaches a plateau at about age 110.
References:
1) Parametric models for late life mortality:
A useful mortality model, which has a logistic form, is: h(x) = (alpha exp(betax))(1+alpha exp(beta*x)). One can also add an additive term, often denoted as gamma or c. Please see for a comparison for late life models:
http://www.demogr.mpg.de/Papers/Books/Monograph5/start.htm
Do you have a link for 3? It would probably affect my answer[0] as I was assuming that the probability of dying between ages x and x+1 increases as a power law after age 60 (which fits well for 60 <= x <= 100, but I don't have data for beyond 100).
The person who asked the question on math.stackexchange.com referred to news reports, and is asking what is essentially a historical question, so the question really should have been asked on a question-and-answer site about historical research rather than on a site about mathematics. That's why the answers are so irrelevant to the nature of the question.
The Nexis commercial database of news stories may be comprehensive enough these days to answer a question like that in detail going back to your own birth year. It would cost money to do the Nexis search, and you'd probably have to pay someone to pore through the search results and edit a document that would accurately summarize the results, but this should be a solvable problem these days.
(As another comment here has already pointed out, the basic answer is "Every time someone becomes the oldest person in the world, that person eventually dies," but I take it that the question actually asked means "How often does the identity of the 'oldest person in the world' change to being a new individual?")
You can't trust the actual data on this one, because the "oldest person alive" is often a deceased Japanese person whose death has not been reported, for the purpose of pension fraud.
Since the question is about the average, it seems the question can be simply answered: the next-oldest person, on average, will die at the same age as the current oldest person. (Obviously, assuming an unchanging mortality rate over time, but this sounds like a valid approximation for very old people. There seem to be a wall around 122.) Thus the average waiting time between two oldest-person deaths is the average age difference between the two oldest living persons.
Edit: actually, an even simpler first-order approximation is possible. If we take at face-value that very old people have a 50% chance of living one more year, and that this statistics holds whatever the baseline date, then upon the death of the eldest person, the average life-span of the next eldest person is 1/2 + 1/4 + 1/8 ... IOW, 1 year.
ps. All are from Japan, US, Italy or UK. I suspect that may be down to record keeping as much as lifestyle.
For example, a friend's wife is from Turkey and doesn't know how old she is as her date of birth was never recorded; one year her parents just made a guess saying "well, you were born in summer and you look like an 8 year old, so we'll stick you down as 21st June 1965".
This seems like one of those interview questions where there is no right or wrong answer, they just want to see your method. I'll probably waste most of my day thinking about this.
[+] [-] StavrosK|13 years ago|reply
It's correct, of course, as the problem is solved, but most people would attempt a ballpark approximation in the end!
[+] [-] cschmidt|13 years ago|reply
[+] [-] crntaylor|13 years ago|reply
[0] http://math.stackexchange.com/a/387581/4873
[+] [-] mturmon|13 years ago|reply
Professor John Wermer tells the story of how, when he was an undergraduate, he took a course in projective geometry from Oscar Zariski, one of the foremost figures in the field of algebraic geometry. Zariski's course was exceedingly general and Wermer, as a young student, was occasionally in need of clarification. "What would you get," he asked his teacher, "if you specialized the field F to the complex numbers?" Zariski answered, "Yes, just take F as the complex numbers."
[+] [-] darkhorn|13 years ago|reply
[+] [-] gjm11|13 years ago|reply
1. At any given time, Pr(oldest person <= age x) = Pr(one person <= age x)^N. So (over time) the median oldest-person age is the (1-2^-1/N) quantile of the age distribution. (For large N, this is roughly 1-log(2)/N.) (You can get that from actuarial tables, or use the Gompertz-Makeham approximation.)
2. So, crudely, the time between oldest-person deaths is comparable to either the expected lifetime of a person of the age found in step 1, or 1/Pr(someone of that age dies in a given year). (Both are approximations. The former will give shorter inter-death times.)
3. According to Wikipedia (which is always right, except when it's wrong), once you get old enough it's a decent approximation to say that that a Very Old Person has about a 50% chance of making it through any given year, and that figure doesn't depend very much on exactly how old they are.
Which would suggest that we should get a new oldest person about once every two years, and that for decent-sized populations (say, 1000 or more) the figure should depend only very weakly on population size.
If #3 is correct and at very advanced ages the mortality rate is roughly independent of age, it seems like this result shouldn't actually depend much on the details of the probability distributions. (The oldest person alive will almost always be very old.)
(You'd get quite different results if, e.g., there were a hard divinely-appointed cutoff at some particular age.)
[+] [-] ademographer|13 years ago|reply
1) Parametric models for late life mortality:
A useful mortality model, which has a logistic form, is: h(x) = (alpha exp(betax))(1+alpha exp(beta*x)). One can also add an additive term, often denoted as gamma or c. Please see for a comparison for late life models: http://www.demogr.mpg.de/Papers/Books/Monograph5/start.htm
In case you speak German, the German Society of Actuaries has an interesting comparison of models: https://aktuar.de/custom/download/dav/veroeffentlichungen/20...
2) An article which estimates the constant hazard at advanced ages: www.demogr.mpg.de/books/drm/007/3-1.pdf
I hope this helps a bit!
[+] [-] crntaylor|13 years ago|reply
[0] http://math.stackexchange.com/a/387581/4873
[+] [-] tokenadult|13 years ago|reply
The Nexis commercial database of news stories may be comprehensive enough these days to answer a question like that in detail going back to your own birth year. It would cost money to do the Nexis search, and you'd probably have to pay someone to pore through the search results and edit a document that would accurately summarize the results, but this should be a solvable problem these days.
(As another comment here has already pointed out, the basic answer is "Every time someone becomes the oldest person in the world, that person eventually dies," but I take it that the question actually asked means "How often does the identity of the 'oldest person in the world' change to being a new individual?")
[+] [-] gwern|13 years ago|reply
I posted a historical response there, so hopefully that settles the issue.
[+] [-] kyllo|13 years ago|reply
[+] [-] gwern|13 years ago|reply
[+] [-] jeremysmyth|13 years ago|reply
[+] [-] pierrebai|13 years ago|reply
Edit: actually, an even simpler first-order approximation is possible. If we take at face-value that very old people have a 50% chance of living one more year, and that this statistics holds whatever the baseline date, then upon the death of the eldest person, the average life-span of the next eldest person is 1/2 + 1/4 + 1/8 ... IOW, 1 year.
[+] [-] JohnLBevan|13 years ago|reply
[+] [-] JohnLBevan|13 years ago|reply
[+] [-] jaynos|13 years ago|reply
[+] [-] sageikosa|13 years ago|reply
[+] [-] Kiro|13 years ago|reply
[+] [-] uptown|13 years ago|reply
[+] [-] unknown|13 years ago|reply
[deleted]
[+] [-] ExpiredLink|13 years ago|reply
tq = teaser question
[+] [-] ttrreeww|13 years ago|reply