(no title)
greenlakejake | 12 years ago
% python
Python 2.7.5 (default, Aug 25 2013, 00:04:04)
[GCC 4.2.1 Compatible Apple LLVM 5.0 (clang-500.0.68)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> i = long(9999999999999999999999999999999)
>>> i
9999999999999999999999999999999L
>>>
masklinn|12 years ago
IIRC, so do Erlang, Ruby or Haskell (when using `Integer`), FWIW. And Java has BigInteger (though that one's a pain to use).
But there's a cost to their existence (they need to check for overflow at every operation), and a cost to going above machine word size. Also, now you've got "integers" which can take arbitrary amounts of memory and integer operations in O(n)
Still, definitely a plus on the correctness side.
There's also the option of type-encoded value ranges as in Pascal or Ada.