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kulkarnic | 11 years ago
The irrational reason is that it's been 60+ years since atomic weapons were deployed, and we are confident the danger has passed. But really, there's plenty of weapons out there: http://www.motherjones.com/politics/2011/11/map-nuclear-bomb...
hga|11 years ago
A serious, concrete underground "hideout" will save you from anything but a really close hit; I can look up numbers if you want, but I maybe remember a good metric is 1MT and one mile of separation, requiring a less intense shelter. And a large fraction of the population can get by with much less, carpet bombing suburbia and exurbia was never going to happen, especially due to counterforce requirements and the Soviets believing that MAD was profoundly immoral and never buying into it.
waynecochran|11 years ago
kulkarnic|11 years ago
Someone|11 years ago
Also, I think most shelters would be far enough from blast areas to provide some protection.
Eizo Nomura (who, amazingly, doesn't have a Wikipedia page) was 170 meter from ground zero in Hiroshima, and survived (http://en.m.wikipedia.org/wiki/Atomic_bombings_of_Hiroshima_...)
Akiko Takakura was above ground at less than 300m and lived for 60 years.
Even though later bombs were much more powerful that makes it likely that shelters at the edge of the blast radius can save lives.
Not all of them, but any program to protect civilians is a statistics game.
All the construction in SF isn't 100% effective against earthquakes, either.
ZanyProgrammer|11 years ago
hga|11 years ago
And most warheads are less powerful (see my other comments); using my handy "RAND" nuclear effects calculator from the back of my copy of The Effects of Nuclear Weapons, 15 PSI for the following weapon air bursts (targeting cities, not ground bursts against ICBMs etc.):
So we're really talking a mile or two, depending on the standards to which the shelters are built. 1 MT 1 mile requires 45 PSI, call it 50 per the above. Don't know how intense a real shelter would have to be, then again that's an uncommon threat level.Retric|11 years ago
The lower 48 states are only 3,119,884.69 square miles if you inclde waterways. With just land it's only 2,959,064.44 square miles.
So, 10k nukes let's you carpet bomb the lower 48 and have one within 10 miles of just about every point. Focus on population centers and I suspect you could easily get 95+% of the population within 5 miles of a detonation.
masklinn|11 years ago
The rational reason we don't build nuclear shelters anymore (which is not actually true by the way, Switzerland still builds them although they're not required anymore for private residences) is because there's very little chance of a massive nuclear war which is what they were for.
> As weapon yields increased, it's become apparent that a concrete, underground hideout is not going to save you.
Weapon yield has decreased, not increased. In the 50s, delivery was through bombers, you wanted big bombs because many bombers were going to be shot down so each nuke delivered had to pack as much punch as it could. Early ICBM had similar-ish issue, you had few inaccurate rockets and they had a warhead each so each warhead had to count, you built a big rocket and a big warhead on top of it, and the ones that didn't fail and weren't shot down razed a city even when they missed it by tens of miles. That's where you had multi-megaton designs
With the 60s and MIRV multi-megaton went online (they'd been designed in the 50s) but systems designed in the 60s and deployed in the 70s for the exact same role all went sub-megaton, half a megaton at most, usually less, for smaller and more precise delivery platforms and MIRV systems.
The most numerous warhead in the US nuclear arsenal is the 100kT W76.
ErikRogneby|11 years ago
jules|11 years ago
dba7dba|11 years ago
Because both leaderships of US and USSR knew starting WW3 would mean end of civilization on the planet, they controlled themselves.
alan_cx|11 years ago