ayepif | 1 year ago | on: Optimizing ML training with metagradient descent
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"Multiply them together and add one. No prime divides the new number (because "every" prime leaves a remainder 1), so you've just produced a new prime. This new prime is larger than the largest prime in your finite set because you multiplied that by the rest of them and added one to get it."
Instead you have created a number that may or may not be prime but definitely requires a new prime number (not in your set) to factorise it. Counter example: Take your set of prime numbers to be {2,3,5,7,11,13} then
(2.3.5.7.11.13)+1 = 30031
30031 factorises into 59.509 so you have found two prime numbers that are not in your original set.
EDIT: Responding to the edit above. The problem is that you claim that you make a new prime number by multiplying them all together and adding one. You didn't multiply all the numbers and added one to get the prime number, you multiplied all the numbers and added one to get a number (POSSIBLY NOT PRIME) whose FACTORS are prime numbers not in your original 'supposed' finite set. Your proof essentially lacks the step: IF new_number is prime: proof finished ELSE: factor new_number and show that at least one of the factors is not in your finite set.
EDIT 2: Counterexample number 2. Suppose your finite set of primes is {2,7} (2.7)+1 = 15 So you have found 3 and 5 as primes that are not in your original set and are SMALLER than the largest prime in your original set. This is now a second mistake in your proof. Whether you are trolling or just too arrogant to see the mistake/error I do not know.
ayepif | 8 years ago | on: Medium tries to prevent people reading deleted articles on the Wayback Machine?
ayepif | 10 years ago | on: Why Russia’s Alternate History of Malaysia Airlines Flight 17 Matters
Source: http://www.ibtimes.com/pro-russian-rebels-have-air-force-mad...
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